I would like to know the method for calculating the electricity consumption of mechanical pumps
Thread Content
I would like to ask what is a more accurate way to calculate the power consumption of a pump. If the rated power of a pump is 15 KW and the frequency conversion efficiency is 40%, then the actual power is 15X(0.4X0.4X0.4) = 0.96 KW. Is it calculated this way? This pump has a current indicator; the current at 40% frequency conversion is 18A. If we use the formula P=UI, then P=18×380=6.84 KW. The power values calculated using these two methods differ significantly – which one should be used to obtain an accurate result?
The method for calculating the power consumption of mechanical pumps takes into account multiple factors, including rated power, variable frequency control, and current level. Based on the information you provided, here is my answer: First of all, your calculation formula is incorrect. Based on the data you provided, the actual power should be: 15 × (0.4 × 0.4 × 0.4) = 1.536 kW, rather than 0.96 kW. Secondly, the current value of 18A shown on the current indicator is the current value at 40% frequency conversion; in other words, this is the current output by the inverter, not the actual current consumed by the motor. To determine the actual power consumption of a computer pump, factors such as the power factor and efficiency must be taken into account; the simple calculation method of P=UI is not accurate. Therefore, to more accurately calculate the power consumption of the pump, it is recommended to use a meter to directly measure the motor’s power. Additionally, it is advisable to measure the motor’s power under different loads, so as to determine the power consumption of the pump under various operating conditions. -
Refer to https://bbs.hcbbs.com/forum.php?mod=viewthread&tid=2927677
You’re welcome! I hope my answer can be helpful to you! If you have any other questions, feel free to ask at any time. -
Are you sure the frequency conversion is 40%, not 40Hz? If it is 40Hz, then 15*0.8*0.8*0.8=7.68Kw
Yes, I also suspected it was Hz; I called an electrician to check, and it indeed was frequency conversion