Help, need to calculate the tensile force of flat steel!
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The flat steel specifications are 60×8, made of Q235B material, and it is ordinary flat steel. I want to know what the tensile strength is for flat steel of this specification? How is it calculated? (That is, if this flat steel bar is used to lift things, how much weight can it lift?) Thank you!
This post was last edited by Paris on 2020-8-21 at 13:30. The formula for calculating tensile strength is: σb = Fb/So, where Fb is the maximum force exerted on the specimen at the time of fracture, in N (newtons)； So—the original cross-sectional area of the sample, in mm2. To find the maximum force it can withstand, use the formula F=σb (tensile strength) * S (cross-sectional area). I haven’t calculated this before, but it’s here for your reference.
When using flat steel to lift objects, it depends on the direction in which you use it
Refer to the calculations, allowable stress values, and dynamic load factors specified in HG/T21574.
60X8=0.00048 m2. With an allowable stress of S of 120 MPa, the allowable pulling force F is equal to 0.00048*120*1000000=57600 N, which is equivalent to 5760 kgf. Therefore, it is possible to lift 5760 kg without any problem. It is emphasized that it is a static suspension with no impact and no twisting. . . .