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Heat exchange area of glass coil condenser

2018-08-09View Original

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Experts: How is the heat exchange area of a glass-coiled condenser calculated? Could you provide a small calculation software? What size heat exchange area should a glass coil condenser have for a 5000L reactor?
Reply #22018-08-09
Is there anyone who is an expert in this area? I need help!
Reply #32018-08-09
This post was last edited by wiseboy on 2018-8-9 at 16:08. You need to provide details about the condensing material; for example: the amount of water vapor being condensed is 1234.56 kg/h, the temperature is 100°C, and the pressure is at atmospheric level. . . . . . . Design is not the problem. Also, what does a calculation utility software mean? Why “small”? !
Reply #42018-08-09
Ha~~ Such small software isn’t a legitimate program like HTRI; rather, it’s an Excel calculation program that has been developed by oneself. Well then, let me show you my calculation results and ask you to help me analyze whether they are correct: 2000 KG of toluene is to be distilled at atmospheric pressure; the distillation is completed in 4 hours. The distillation temperature is T1=110°C, while the target cooling temperature is T2=40°C. Circulating water is used for cooling, with an inlet temperature of t1=30°C and an outlet temperature of t2=42°C. The heat fusion value of toluene is C1, and its latent heat of vaporization is r1. The calculated results are as follows: the flow rate of toluene is M1 = 500 kg/h. Since the condensation process involves a phase change, the heat required to cool the toluene is given by: M1*C1*(T2-T1)+M1*r1 = 33.61 KW. The average heat transfer temperature difference is: △tm = ((T1-t2) – (T2-t1)) / Ln((T1-t2)/(T2-t1)) = 30.26°C. With K = 395, the heat transfer area is: A = Q/K*△tm = 33.61*1000/395*30.26 = 2.81 m2. Expert, could you please check whether these calculation results are correct? ? Thank you so much!
Reply #52018-08-09
Is there anyone who can help me check if the calculations are correct?
Reply #62018-08-09
This post was last edited by wiseboy on 2018-8-9 at 17:10. By setting K=395, your calculations become completely meaningless. This approach of choosing K is far too crude and lacks seriousness. I refuse to engage in such “calculations”. :D
Reply #72018-08-09
I have a question: how should K be chosen? Are there any issues with my other calculations? Especially the heat involved in the toluene phase transition
Reply #82018-08-09
Could you help me calculate how large a heat exchange area is needed?
Reply #92018-08-09
The last edit to this post was made by wiseboy on 2018-8-9 at 17:21. Throughout, I haven’t seen any information regarding the dimensions of your heat exchange tubes, the diameter of the coils, the spacing between the coils, the material used, or the thermal conductivity – parameters that are closely related to heat transfer. Just this alone means it’s not a heat transfer calculation; other issues need not be mentioned.
Reply #102018-08-09
Then, according to the heat exchange requirements I mentioned, could you help me calculate the heat exchange area? If it’s convenient! I accept your criticism with an open mind, and I hope you can teach me as well
Reply #112018-08-09
The data you mentioned, such as the dimensions of the heat exchange tubes, the diameter of the coils, and other sizes, are used when calculating the specific dimensions of the heat exchanger as well as the amount of cooling water required – these are aspects that fall within the scope of equipment engineering. I'm currently doing process calculations, and I only need to calculate the heat exchange area; therefore, those equipment parameters you mentioned aren't relevant here

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