How to calculate the volume ratio of nitrogen, oxygen, and water vapor
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For saturated steam at 80 degrees Celsius, how can the volume ratio of nitrogen, oxygen, and water vapor be calculated?
The question is vague and the conditions are insufficient; I don’t know what you want to do
In saturated air at 80 degrees, the partial pressure of water vapor is 0.047359 Mpa, while the atmospheric pressure is 0.101 Mpa. Since the pressure ratio is equal to the molar ratio, it is assumed that water vapor accounts for 46% of the volume of the currently saturated air. What I want to know is what proportion of the volume is occupied by nitrogen and oxygen in this case
The original volume ratio of nitrogen to oxygen in air is 79:21. Currently, water vapor accounts for 46%; therefore, nitrogen = (1-0.46)*0.79*100% = 43%, and oxygen = (1-0.46)*0.21*100% = 11%. Is that correct?