Seek advice on calculating the heat exchange area of a two-effect counter-current forced-circulation evaporator
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Dear experts, for the concentration of sulfuric acid solution – with a processing capacity of 24 T/h, from 10% concentration to 46% for crystallization and separation – a two-effect counter-current forced-circulation evaporation process is used. The saturated steam pressure in the first effect is 0.3 MPa, while the relative pressure in the second effect is -0.06 MPa. What area are required for the heaters in each of the first and second effects?
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The last edit to this post was made by sdlkx on 2021-12-9 at 20:31. The pressure in the first stage is -0.03 MPa, the evaporation temperature is 97°C; it’s a saturated sulfuric acid aqueous solution, with a boiling point increase of about 8°C. The pressure in the second stage is -0.068 MPa, and the evaporation temperature is 78°C. The temperature of the feed material after passing through the preheater is around 50°C. Based on my preliminary calculations, the heat exchange area for the first stage is approximately 800 m2; I’m not sure how accurate these figures are
We have done one unit of 5 tons; the heat exchange area is 240 square meters, with pipes of 38 diameter
If that’s the case, then 1,000 square meters are needed? Are the areas of the first and second effects the same?
The first and second effects correspond to the shell side, where the material is different; everything else is the same
After some calculations, the total heat exchange area is approximately 130㎡; 1.9 kg of water is vaporized per second, with a power output of 4.22 MW
This is the thermal equilibrium I simulated using Aspen; each stage can evaporate around 10 T of water. Based on the heat load per stage, the required area is over 880 m², right? Could you please tell me how you calculated it?