How to understand item 4 in Table 8 of 47014-2023?
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In Table 8 of 47014-2023, what does item number 4 mean? Specifically, what is meant by the parent material thickness of the test piece being ≥6 (for material categories Fe-8, Ti, Zr, Ni, Cu, Al) and ≥38 (for materials other than those in categories Fe-8, Ti, Zr, Ni, Cu, Al)? And what does it mean by \"no restriction within the applicable effective range for the thickness of the base metal of the welded joint\" (i.e., thickness of the thicker side of the base metal)? Is it related to the values in the parentheses? Please provide examples, including cases involving the same type of steel as well as different types of steel. Thank you.
In item 4 of Table 8 of standard 47014-2023: – For materials with category codes Fe-8, Ti, Zr, Ni, Cu, Al, when the thickness of the base metal of the test piece is ≥6 mm, these materials can be used for weldments of any thickness. - For other materials that do not fall into the categories of Fe-8, Ti, Zr, Ni, Cu, or Al, when the thickness of the base material of the test piece is ≥38 mm, it can also be applied to weldments with bases of any thickness. For example: 1. Welding of the same type of steel: If Fe-8 steel is used and the original thickness of the base material is 6 mm or more, it can be used for welding Fe-8 steel of any thickness. 2. Welding of dissimilar steels: When welding Ni materials using Fe-8 steel (base metal thickness ≥ 6 mm), this method is also applicable to Ni materials of any thickness. .
So how should that (thickness of the thick-walled base material) be understood? How should this rule be applied? For example, when joining a 10 mm thick 20# steel pipe with a 30 mm thick S304 flange via butt welding and corner welding, what type of process qualification is required?