I need to install a thermoresistor on a DN200 pipe
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I need to install a thermal resistor on a DN200 pipe. What does “L/l=450/300” indicated on the drawing mean? Is it the insertion depth? Isn’t this too long? Please help!
You can determine the insertion depth yourself; simply weld a fitting onto the main pipe to solve it
If it is a heat-insulating pipe, this design works fine. For example, with an insertion depth of 100, a heat-insulation layer of 100, and 100 reserved for bolt installation, the total is 300; subtracting 300 leaves 150 as the distance between the junction box and the interface
450 should be the total length, and 300 is the insertion depth; after accounting for the flange stub, the insertion depth into the pipe is approximately 150. You need to check the installation diagrams to determine whether the design is correct. Spit: L
L/l=450/300, insertion depth 300, total length 450. But you only have a 200 diameter pipe. . . 300/150 is still appropriate. . . .
L/l=450/300, insertion depth 300, total length 450. But you only have a 200 diameter pipe. . . 300/150 is still appropriate. . . .
L/l=450/300; the total length is 450 and the insertion depth is 300. If it’s a loop, then a shorter insertion depth will suffice
A 200mm pipe with a penetration depth of 300mm is a bit long; the length of the part that goes into the pipe can be set to 100mm. If there is no insulation layer, the length of the thermometer probe can be 80mm, in which case the total penetration depth would be 100 + 80 = 180mm (or 200mm can also be chosen)； If the pipeline is insulated, a 120 size can be selected for the thermometer nozzle; in that case, the insertion depth will be 100 + 120 = 220. The manufacturer can determine this value based on their product specifications.
Maybe the mounting base is quite long~:lol