When does this logic output 0?
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Figure 3 shows the question I asked. My understanding is as follows: According to Figures 1 and 2, when the input at terminal S is 0, the output is independent of it, and the output is 1 ； When the input to S is 1, S=1 and R=1; S is output first, resulting in a value of 1. I’m a newcomer to the chemical industry; I’d like to ask for advice from those with more experience.
The last edit to this post was made by zhbst on 2018-4-15 at 12:39. Figure 4 is not clear; for the RS flip-flop, when s=0 and r=0, the output is 0； When s=1 and r=0, the output is 1 ； When s=1 and r=1, the output is 1 ； When s=0 and r=1, the output is 0. You should look up books on digital circuits for this.
The flip-flop in Figure 4 has S priority; therefore, when the AND gate in front of the flip-flop outputs 0, the final output of the flip-flop (after inversion) is 0.
I looked up some information and understood it. You’re right, and in this diagram, because there is a NOT gate, the output has the opposite value. Thank you