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Seeking a solution

2019-01-23View Original

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Seeking a detailed answer to this reverse problem
Reply #22019-01-23
Not the topic, but the attitude toward asking questions. Good luck!
Reply #32019-01-25
Whether it is a two-wire or four-wire system, the transmitter acts as a constant current source
Reply #42019-01-25
1. The question is terrible; it’s hard to even express oneself clearly. 2. In this question, “two-wire instruments and four-wire instruments” refer to transmitters with a 4–20mA output. 3. When the supply voltage meets the requirements and the wire resistance in the current circuit is below the allowable value, then neither the output nor the transmission of the current signal is attenuated, and there is no loss due to wire resistance. 4. “Resistance between wires: 12kΩ”. The teacher who came up with this question is really annoying; he’s complaining for no reason. It’s about measuring the resistance between two wires that are connected across the terminals of the transmitter and across the terminals of the power supply. What’s the point of that? What is he trying to convey? This teacher is truly too meddling. 5. “Relationship between the instrument display value and the actual value” – By instrument here, does it refer to the transmitter? Do the values displayed on the instrument here refer to those shown on the transmitter’s gauge? The table header can display the original measured value, a percentage, or some calculated value. . . What exactly does this teacher want to know about the ball’s properties? Moreover, the value displayed on the transmitter’s gauge is not a measurement used for evaluation; it is merely a reference value for observation. 6. This teacher is an idiot; he’s too silly. I can’t understand him. He’s supposed to do problems, not draw things like “equivalent circuits”. The older brother can’t understand it.

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