Under normal conditions, is there a voltage present between the positive terminal on the output side of the isolated safety barrier and ground?
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As the title suggests, under normal conditions, is there a voltage relative to ground at the + terminal on the field side of an isolated safety barrier? What is the voltage corresponding to that energy? If energy is converted into voltage, please explain the principle and how the circuit is formed. Thank you! If it’s not possible, is it because it’s a floating ground? Some people say that any voltage can be measured; I’m not sure if that’s true Thank you~
No one answered. I have measured the secondary side of numerous safety gates with normal output, and the results showed voltages ranging from a few tenths to a few volts. Therefore, I believe that when the safety gate is functioning properly, there is indeed a voltage at its output terminal with respect to ground, though it’s quite low. Theoretically, however, this voltage should not form a circuit; hence it might be impossible to detect it. Could it be an induced voltage? So I would appreciate some advice from those who are more experienced, thank you!