Help: Ethylene loss in the demethanizer
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The higher the ratio of methane to hydrogen, the greater the partial pressure of methane, and the less ethylene is lost. Why is that?
The higher the ratio of methane to hydrogen, the greater the amount of methane, resulting in a larger proportion and a higher partial pressure. With less hydrogen, there is less loss of ethylene.
The newly published book on methanol-to-olefins provides a detailed introduction. You can refer to this book
What is the relationship between a decrease in hydrogen and ethylene loss?