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In low-temperature methanol washing, the exhaust gas passes through an exhaust gas scrubber; why do both the exhaust gas and the desalinated water lose temperature? Is there anyone who knows this and can provide a detailed explanation? I have a question bank here, but I don’t quite understand it. It’s easy to grasp the idea that exhaust gas is dry gas – meaning that the moisture has evaporated, leaving the gas saturated. However, I’m not sure about the concept of gas saturation
It was stripped, so it became gas-saturated. PS: This question bank wasn’t probably created by your company itself; it resembles the style of our Haiyou – each sentence seems to have been written by a different person
The process of CO2 gas saturation involves water transitioning from the liquid phase to the gas phase; this phase change absorbs heat, resulting in a decrease in water temperature. Heat transfer and mass transfer with the CO2 gas further lower the temperature of the CO2 gas
First of all, a decrease in the medium temperature definitely implies the presence of a source of cooling energy
The original gas is dry gas; no further explanation is needed once this is understood. It enters the water scrubber, where, under certain operating temperatures and pressures, water is introduced into the exhaust gas stream so as to evaporate – that is, to reach a saturated state – and this process absorbs heat
Could you explain it in detail? I’m afraid I might not understand it correctly