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My understanding is that if the gas on one side of the bearing housing is blocked at the cross tube, then the liquid level on the other side of the cross tube (the side of the oil reservoir) will be slightly higher. The constant-level oil reservoir cannot come into contact with the atmosphere, and it is unable to refill itself automatically. If the gas in the bearing box is not held back, it flows to the other side through the cross tube and eventually escapes through the holes in the oil cup. As a result, the pressure in the bearing box returns to atmospheric pressure; the liquid level in the cross tube (on the side of the oil cup) drops, and the constant-level oil cup automatically replenishes the oil. I’m not sure if my analysis is correct – could anyone with more expertise please provide an explanation?
This post was last edited by liaifeng on 2018-5-7 22:01. The sealing of the bearing housing in ordinary pumps is probably better for liquids, but it seems that the sealing effect for gases isn’t as good as you claim If we follow your line of thinking, the first point to be identified should be the lowest oil leakage site. P But your approach to learning is quite good – it has a bit of the \"four understandings and three abilities\" spirit! I recommend you take a look at: http://www.aufine-pv.com/zhishi1.asp?id=1833##1
The working principle of a constant-level oil cup is based on the principle of a communicating vessel; once you understand that principle, you’ll know how it functions. Try filling a water bottle with water, turning it upside down in water so that no water leaks out of the opening, and see if the liquid level inside changes. Find another transparent hose, fill it with some water to form a U-tube, and check whether the liquid levels on both sides are the same. Then change the shape of the bottom part of the U-tube and see again if the liquid levels on both sides remain equal.