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One question per day: 6 wealth points for correct answers, 2 wealth points for participation, Question 222

2015-06-14View Original

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The purity of calcium carbide is 80%, and the gas generation rate is 1900 m3 per hour. How many tons of calcium carbide are required? A、 6.2 B、 6.5 C、 6.8 D、7 C
Reply #22015-06-14
The purity of calcium carbide is 80%, and the gas generation rate is 1900 m3 per hour. How many tons of calcium carbide are required? (C) A、 6.2 B、 6.5 C、 6.8 D、7
Reply #32015-06-14
I think the answer should be 6.8 tons
Reply #42015-06-14
The purity of calcium carbide is 80%, and the gas generation rate is 1900 m3 per hour. How many tons of calcium carbide are required? (C) A、 6.2 B、 6.5 C、 6.8 D、7
Reply #52015-06-14
Solution: CaC2 + 2H2O → C2H2 + Ca(OH)2; energy released: 30.4 kcal/mol. 64 kg, 22.4 m3; x kg, 1900 m3. 64 : x = 22.4 : 1900 → x = (64 × 1900) / 22.4 = 5482.57 kg. 5482.57 kg ÷ 0.8 = 6785.71 kg. Therefore, 6785.71 kg of calcium carbide with 80% purity is required, which is approximately 6.8 tons
Reply #62015-06-15
The purity of calcium carbide is 80%, and the gas generation rate is 1900 m3 per hour. How many tons of calcium carbide are required? C. 6.8 CaC2 + 2H2O ------ C2H2 + Ca(OH)2 + 30.4 kcal/mol. 64 kg, 22.4 m3; x kg, 1900 m3. 64 : x = 22.4 : 1900 → x = (64 × 1900) / 22.4 = 5482.57 kg. 5482.57 kg ÷ 80/100 = 6785.71 kg
Reply #72015-06-15
The purity of calcium carbide is 80%, and the gas generation rate is 1900 m3 per hour. How many tons of calcium carbide (C, 6.8) are required? A、 6.2 B、 6.5 C、 6.8 D、 7 Solution: CaC2 + 2H2O → C2H2 + Ca(OH)2; energy released = 30.4 kcal/mol. 64 kg, 22.4 m3; x kg, 1900 m3. 64 : x = 22.4 : 1900 → x = (64 × 1900) / 22.4 = 5482.57 kg. 5482.57 kg ÷ 80/100 = 6785.71 kg. Answer: 6785.71 kg of calcium carbide with 80% purity is required
Reply #82015-06-15
The purity of calcium carbide is 80%, and the gas generation rate is 1900 m3 per hour. How many tons of calcium carbide are required? (C)

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Translated at 2026-07-21 02:14:10

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