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2015-06-16View Original

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1. The initial temperature for a certain chemical reaction is 25°C; when the temperature increases by 12°C, the reaction rate doubles. What is the activation energy of this reaction in J/mol? (A) 44364 (B) 49986 (C) 52928 (D) 63769

Reply #22015-06-16

Calculated using the Arrhenius equation lnk=lnA-Ea/RT

Reply #32015-06-16

It should be A, right? lnK1 = lnA – Ea/RT1……(1)； lnk2=lnA-Ea/RT2……(2) ； (2) – (1) to find Ea

Reply #42015-07-28

ln(k2/K1) = -Ea(1/T2 – 1/T1)/R; that is: ln2 = -Ea(1/310 – 1/298)/8.314, and Ea = 44364

Reply #52015-07-28

Please experts advise whether the above calculations are correct

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