Regarding the pump head
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Now, a pump needs to be selected with a flow rate of 20 m3/h, a medium density of 1100, and an outlet pipe diameter of DN80. The delivery distance is: 7 meters up a pipe rack first, followed by 300 meters at the same elevation. What should be the head required for this pump? How to calculate
By experience. 5 kilograms of head is sufficient. . . .
Calculated based on pipeline losses: a 7-meter vertical pipeline results in a loss of 0.07 MPA; one elbow causes a loss of 0.02 MPA; 300 meters of horizontal pipeline result in a loss of 0.05 MPA. The total loss is 0.14 MPA, for reference only
There’s not even viscosity; you all calculate it yourselves, calculate the resistance – check the textbook on chemical engineering principles
This still needs to be calculated; it’s possible to get an approximate estimate though
I chose a head of 50 meters; that should be sufficient, right?
As for the viscosity of the material, please tell me what kind of material it is; if the viscosity isn’t high, 50 m is sufficient
This post was last edited by sword77 on 2015-8-5 21:47. Inlet: (1) Operating pressure of the equipment: P1, (2) Static head: P3, (3) Pressure drop in the inlet pipeline: 0.05 MPa(g). Outlet: (1) Boundary zone pressure: P2, (2) Static head: P4 = 1100*7*0.00001 = 0.077 MPa(g), (3) Pressure drop in the outlet pipeline: 0.15 MPa(g). Head = (P2 + 0.077 – 0.15 – P1 – P3 – 0.05) * 100000 / 1100
I think 50m is enough! :D
There is no viscosity – how do you calculate the pressure loss? Is it just an estimate? The others can all be calculated using Bernoulli’s equation!