One question per day; those who answer correctly receive 6 wealth points, while participants receive 2 wealth points； Question 288
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The gas generation volume of calcium carbide is 280 L/KG; what is the amount of water that needs to be added when 2000 m3 of acetylene gas is produced per hour? Assume the calcium carbide contains 15% CaO, with no loss considered. A、3214 B、3559 C、3444 D、4000 Answer: B、3559
The gas generation volume of calcium carbide is 280 L/KG; what is the amount of water to be added when 2000 m3 of acetylene gas is generated per hour? (B) Assume the calcium carbide contains 15% CaO, with no loss considered. A、3214 B、3559 C、3444 D、4000
The gas generation volume of calcium carbide is 280 L/KG; what is the amount of water to be added when 2000 m3 of acetylene gas is generated per hour? (B) Assume the calcium carbide contains 15% CaO, with no loss considered. A、3214 B、3559 C、3444 D、4000
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The gas generation volume of calcium carbide is 280 L/KG; what is the amount of water to be added when 2000 m3 of acetylene gas is generated per hour? (B) Assume the calcium carbide contains 15% CaO, with no loss considered. A、3214 B、3559 C、3444 D、4000 Solution: CaC2 + 2H2O → C2H2 + Ca(OH)2; energy released = 30.4 kcal/mol. 64 kg × 36 = 22.4 m3; 2000 m3. x = (64 × 2000) / 22.4 = 5714.29 kg. Total calcium carbide used: 5714.29 kg ÷ 80% = 7412.86 kg. Amount of CaO in this total amount: 7412.86 kg × 15% = 1071.43 kg. The amount of water required for the complete hydrolysis of CaC2 is: 64 / 5714.29 = 36 / x1; thus, x1 = (5714.29 × 36) / 64 = 3214.29 kg. For the reaction CaO + 56H2O → Ca(OH)2, the ratio is 56 / 1071.43 = 18 / x2; therefore, x2 = (1071.43 × 18) / 56 = 344.39 kg (water required for CaO). Total water needed = x1 + x2 = 3214.29 kg + 344.39 kg = 3558.68 kg. Answer: The amount of water that needs to be added is 3558.68 kg
Shaba, I’ve changed the data inside; didn’t you see it?
The gas generation volume of calcium carbide is 280 L/KG; what is the amount of water to be added when 2000 m3 of acetylene gas is generated per hour? (B) Assume the calcium carbide contains 15% CaO, with no loss considered. A、3214 B、3559 C、3444 D、4000
The gas generation volume of calcium carbide is 280 L/KG; what is the amount of water to be added when 2000 m3 of acetylene gas is generated per hour? (B) Assume the calcium carbide contains 15% CaO, with no loss considered.
It should be B; the original poster, please provide the correct answer. Haha:)
The gas generation volume of calcium carbide is 280 L/KG; what is the amount of water that needs to be added when 2000 m3 of acetylene gas is generated per hour? Assume the calcium carbide contains 15% CaO, with no loss considered. A、3214 B、3559 C、3444 D、4000 My answer is: C
B、3559 Solution: CaC2 + 2H2O → C2H2 + Ca(OH)2; energy released: 30.4 kcal/mol. Mass of CaC2: 64 kg; mass of Ca(OH)2: 36 kg; volume required: 22.4 m3; conversion factor: 2000 m3 per unit mass. Therefore, x = (64 × 2000) / 22.4 = 5714.29 kg. Total amount of calcium carbide needed: 5714.29 kg ÷ 80% = 7412.86 kg. Amount of CaO in this total amount: 7412.86 kg × 15% = 1071.43 kg. The amount of water required for complete hydrolysis of CaC2 is calculated as follows: 64 : 5714.29 = 36 : x1; thus, x1 = (5714.29 × 36) / 64 = 3214.29 kg. For the reaction CaO + H2O → Ca(OH)2, the ratio is 56 : 18. Therefore, x2 = (1071.43 × 18) / 56 = 344.39 kg. Total water required = x1 + x2 = 3214.29 kg + 344.39 kg = 3558.68 kg. Answer: The amount of water that needs to be added is 3558.68 kg