Is it feasible to use a stainless steel pipe with an outer diameter of 60 mm and a wall thickness of 3.5 mm to withstand a pressure of 16 MPa?
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Is it too bold? Is it dangerous?
Use the formula to calculate it! ! The formula for the cylinder wall thickness is P*Di÷(2*σ*η－P); don’t forget to include the deviation and rounding factors
This post was last edited by yjjpedp on 2015-8-30 08:21. Based on calculations using 30408 stainless steel, a stress of 116 MPa is required; the welding factor is 1. The wall thickness is calculated as 16 * (60 – 3.5 * 2) / (2 * 116 * 1 – 16) = 3.93 mm. A negative deviation of 0.4 mm is applied to the pipe thickness. Since the medium in question is unknown, a corrosion allowance of 0.25 mm is assumed (based on a service life of 20 years and a corrosion rate of 0.0125 mm/year). The resulting wall thickness is 4.58 mm, which is rounded up to 5 mm. 3.5mm is less than 5mm; conclusion: 100% not feasible. No one could make such a basic mistake – the poster should check whether it’s 1.6MPa
The 4th floor is impressive; PN16 does not mean 16 MPa. Hehe
I see, I understand now; it seems dangerous even to me when I look at it
The 4th floor is amazing; could you tell me the source of the formula?
If you’re not good at doing the calculations, hire someone who specializes in pipeline work – don’t take that risk yourself. An accident can have serious consequences; 15 people died in a liquid ammonia leak in Baoshan because the owner tried to save money by drawing the plans himself and hiring an ordinary welder to carry out the work, without even preparing proper weld joints. As a result of the accident, he lost everything he had. It’s better not to skimp on this amount of money.
I’ve learned it; it’s just enough to be useful…
The inner diameter is 60, I guess; a specification with an outer diameter of 60 isn’t common