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How is the residence time in the buffer tank determined? I tried many criteria but couldn’t find it

2016-03-28View Original

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Q: How is the residence time in the buffer tank determined for Xiao Xue? I’ve looked through many standards but couldn’t find any regarding the relationship between hydrogen production units and hydrogen purification units, specifically for producing 600 m³/h of hydrogen. @jacques0920 @ylb913 @EngineeringStudent @WangTianze @WangTianze @ChemicalEngineeringTalk
Reply #22016-03-28
If it’s a gas, it usually takes a few seconds; if I remember correctly, it’s 5-10 seconds
Reply #32016-03-28
For gases, it usually takes a few seconds, approximately 5-10 seconds
Reply #42016-03-28
This post was last edited by cflt111 on 2016-3-28 at 18:01. The amount of gas stored in this hydrogen tank can be easily calculated. If the volume V is 100 m3 and the pressure P is 1.1 MPa (A) ≈ 11 atm, then the maximum amount of gas that can be released from the tank occurs when its pressure equals atmospheric pressure; beyond that point, no more gas can be discharged. Therefore, the volume of gas released, V’, is given by: V’ = (P – Po) / Po * V = (11 – 1) / 1 * 100 = 1000 Nm3. With this amount of gas available, if the consumption rate is high, say 15000 Nm3/h, then the buffer time would be 1000 / 15000 = 0.0667 hours, which is equivalent to 240 seconds. You did not specify whether your gas consumption is in standard cubic meters or in terms of volume under specific conditions. If it is in standard cubic meters, that is, 15,000 Nm3/h, then the maximum buffering time is 240 seconds. If the gas consumption is 15,000 m3/h at a pressure of 1 MPaG, then the buffering time is only 24 seconds. However, you need to consider this scenario carefully: when the tank releases 100 m3 of gas under these conditions (which equals 1,000 Nm3, due to the 10-fold difference in pressure), the pressure inside the tank drops to atmospheric level, while the subsequent process requires a pressure of 1 MPaG. Therefore, such a 24-second buffering time does not exist, as the gas cannot be released; buffering requires a pressure difference, meaning that the pressure in the subsequent process must be lower than the pressure in the storage tank. The gas output volume can be calculated using the formula V’ = (P_tank – P_usage) / Po * V. For example, in the case of an instrument air buffer tank, if the user requires a pressure of 0.2 MPaG, then this tank will have 800 Nm3 of gas available for buffering, calculated as (1.1 – 0.3) / 1 * 100. . The principles and formulas are quite simple; the original poster can calculate them by themselves. I’m not an expert; you might find the content above helpful. Thank you.
Reply #52016-03-29
Lele is great! In which standard is this time specified? Can’t find it?
Reply #62016-03-29
Bro, I’ve seen something similar in some high-class posts! This is to calculate the buffer time given the volume of the storage tank. What if we design a buffer tank? How is this residence time determined?
Reply #72016-03-29
I think this residence time should be determined by the requirements of the subsequent process systems; in the event that the hydrogen production unit stops operating, the gas in the buffer tank must supply the downstream processes for a certain period of time.
Reply #82016-03-29
This question. Could you help again? Is it correct to say that liquid buffer tanks are all horizontal while gas buffer tanks are all vertical? http://bbs.hcbbs.com/thread-1576143-1-1.html (Source: Haichuan Chemical Industry Forum)

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