How ammonia plants determine the amount of water vapor required in the gas generation furnace based on the hydrogen content in semi-water gas

Thread Content

It is known that the volume of semi-water gas is 100,000 m3, with a hydrogen content of 45%, a pressure of 1.9 MPa, and a temperature of 35°C. The steam temperature in the gas generator is 200°C and the pressure is 26 KPa. How can the amount of steam required for the gas generator be calculated? Here are my own calculations: The hydrogen content in semi-water gas is 45,000 m3. At 1.9 MPa/35°C, the density of hydrogen is 1.4787 kg/m3. Therefore, the mass of hydrogen is 1.4787 * 45,000 = 66,541.5 kg. The molar mass of hydrogen is 66,541,500 / 2 = 33,270,750 moles. Since 1 mole of water vapor produces 1 mole of hydrogen, the amount of water vapor required is 33,270,750 * 18 = 59,887,3500 grams, which is approximately 600 tons. Why is the calculated amount of steam so large? I feel like there’s definitely something wrong; I just don’t know what it is. I hope the experts here can help me figure it out