Thread Content
A large wooden basin was filled with a lot of water, and on top of the water there was a smaller wooden basin, inside which there was an iron block. Now, take this iron block and put it directly into the water in the large wooden basin. Has the water level in the large wooden basin risen or fallen compared to before?
The density of iron is greater than that of water; therefore, when an iron object is placed in water, the volume of water displaced decreases, and as a result the object sinks
The volume of water displaced by the iron bar is definitely less than the volume displaced by the small basin.
Can it stay the same? Anyway, the contents in the big basin are already that heavy
The displacement required to float an iron block is much larger than the volume of the block, causing the water level to drop.
When the iron block is placed in the wooden basin, the buoyant force exerted by the water is equal to the sum of the weight of the small wooden basin and the iron block. When the iron block is placed directly in the large wooden basin, a solid iron block will sink to the bottom; at this point, the bottom of the basin exerts a supporting force on the iron block. According to the principle of force balance, the buoyant force exerted by the water on the iron block is less than the weight of the iron block. Consequently, the total buoyant force exerted by the water on both the wooden basin and the iron block is reduced. Using the formula F=ρgv, since F decreases, V also decreases, which means the water level drops. If the iron block is not solid, it may remain suspended or float in the large wooden basin, in which case the buoyant force exerted by the water remains unchanged