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Calculation for heating R22 in a jacketed vaporization tank

2016-10-17View Original

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It is necessary to determine the unsteady-state equilibrium relations regarding time; I’m not sure where to start. I hope experienced experts among you can help: Q – jacket heating, with steam flowing through the jacket. Heat the F22 to vaporize it. Given the steam pressure and temperature, the F22 pressure and temperature, the volume of the storage tank, and the total mass of F22, how can one derive the heat balance equation related to time? ? ? ? ?
Reply #22016-10-17
I’ll take it on myself. . . . :Q:'(
Reply #32016-10-17
This post was last edited by wiseboy on 2016-10-17 22:44. Firstly, it is not recommended to use a jacket; instead, steam coils should be used for heating – it is more efficient and easier to manufacture. Secondly, this process can be perfectly calculated using coil heat exchange software, allowing for the design of the equipment dimensions.
Reply #42016-10-21
Thank you for your reply. What I’m calculating now refers to existing devices. The data only knows the temperature of import and export; parameters such as area and thickness are unknown.
Reply #52016-10-21
I can’t find any relevant calculations for heat exchange in jacketed vaporization tanks. Is there anyone who can provide some guidance?~~~~~~~~~~~~~~:'(:'(:'(:'(:'(:'(
Reply #62016-11-01
If I calculate under the assumption that only the temperature at phase change remains constant, is it feasible to use latent heat? ? ?
Reply #72016-11-08
If all the water vapor condenses and the enthalpy change of the cooled water resulting from the condensation of the water vapor is ignored, then the evaporation amount of F22 = (mass flow rate of water vapor * time * latent heat of vaporization of water vapor – energy lost due to natural convection in the air) / latent heat of vaporization of F22
Reply #82016-11-21
Thank you~ This formula is also the basic formula I took into consideration. The heat transfer on the side surface is related to time and the liquid level, but it is not clear how the thermodynamics at the evaporation surface change. Do you have any ideas?

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