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Closed-loop systems, water pump head, and issues related to the pressure in the circuit system.

2017-10-27View Original

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The last edit to this post was made by hhhljc on 2017-10-28 at 10:00. So, is the total pressure generated by head loss equal to the pressure in the pipeline plus the pressure generated by head loss? For example, if the pressure in the pipeline is adjusted to 0.4 MPa and the head of the water pump is 5 meters, which equals 0.05 MPa, then when the pump is turned on, the total pressure in the pipeline will be 0.45 MPa, is that correct? What other issues should be considered when using a pump in a closed loop? An expansion tank was added.
Reply #22017-10-27
Does anyone know? Is it calculated this way, for a closed loop?
Reply #32017-10-28
A head of 5 meters corresponds to 0.05 MPa, right? In a closed system, the pipeline pressure should be equal to the system resistance, which includes the dynamic pressure of the fluid and the frictional losses along the pipeline. The final result is that the pressure difference between the inlet and outlet of the pump = dynamic pressure of the fluid + frictional loss along the flow path
Reply #42017-10-28
Hello, if this closed-loop system requires a second loop for water replenishment, then is the external pressure of this closed loop 0.45 MPa?

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