Relevant calculation formulas for chillers
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Cooling water flow rate: L = (Q1 + Q2) / △t * 1.163 * (1.15–1.2). Cooling water flow rate: L = (refrigeration capacity of the unit + input power of the unit) * 0.172. Q1 represents the total cooling load multiplied by the utilization rate, in KW units; Q2 represents the power consumption of the compressor (input power), in KW units. L is the cooling water flow rate, in m3/h. △t is the temperature difference between the inlet and outlet water, in °C. Flow rate of the chilled water pump: L (m3/h) = Q (KW) / (4.5–5)°C * 1.163. Flow rate of the chilled water pump = Refrigeration capacity * 0.172. Can all of these four formulas be applied? What is 1.163? 1.15～1.2 is probably the margin given, right? What formula is this, G=1.1*3.6Q/（ρ*c*△T）? What I saw online is that G represents the flow rate of the water pump in m3/h, Q represents the total load on the system, W represents the temperature difference between the supply and return water temperatures, ρ is the density of water at 1000 KG/m3, and c is the specific heat capacity of water at 4.2*103 J/(KG*℃). The results obtained seem incorrect; I would be very grateful if an expert could help me out. I’m a complete beginner and am still learning, so any assistance is greatly appreciated
I work in the lithium battery industry, focusing on the operation of factory equipment, particularly those related to cleanrooms and clean air conditioning systems. I am just starting to get involved in equipment selection and installation processes; please give me your guidance
The moderator is replying to @Zhang Xinlin from Binglun Environment
The method for calculating water flow rate has been identified: 1. Temperature difference flow rate method: Q = Cp × r × Vs × ΔT. Where Q represents the heat load in KW; Cp is the specific heat at constant pressure in KJ/kg·℃ (value: 4.1868 KJ/kg·℃); r is the specific weight in Kg/m3 (value: 1000 Kg/m3); Vs is the water flow rate in m3/h; and ΔT is the temperature difference in ℃