Thread Content
Can the reinforcement range B of the nozzle opening on the flange cover not exceed the calculated inner diameter DC of the flange cover?
When you calculate the opening on the flange cover, the software will ask you for the maximum opening diameter on the flange cover. You can try to enter it. Generally speaking, it cannot exceed 1/3 of the nominal diameter.
Is there such a saying? I think there is no requirement for the aperture diameter for a single opening of 150. The calculation method may be related to the size of the hole.
If it is less than 0.5D, it will be calculated as opening reinforcement, and if it is greater than or equal to 0.5D, it will be calculated as reverse flange.
You didn't understand me. When a pipe is welded to the flange opening and the pipe is close to the edge, the reinforcement range B=max(2dop,dop+δn+δt) during reinforcement calculation, but the reinforcement range cannot exceed the calculated inner diameter Dc?
You didn’t understand what I meant. When I talked about the reinforcement range, you said the maximum opening diameter.
You know the regulations on the scope of reinforcement, so why are you asking?
I don't even understand the drawings? Why do we need to strengthen it? I'm a layman
As long as the hole is opened, it will be weakened, and if there is any weakening, it must be strengthened. The amount of weakening must be compensated, so there is the equal area method. If the weakened relative shell is too large, the analysis and calculation will exceed it. If it exceeds the analysis method, we will find another way and develop the pressure area method. There will always be a way to overcome any difficulties. :handshake