How to determine the azimuth of pipeline forces for the SW6 tower?
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When calculating in the SW6 column for pipe forces that are perpendicular or parallel to the container’s centerline, how should the azimuth angle of the pipe force F be entered? With the X direction as the reference, how is the X-axis established?
It is related to the orientation of the pipe end being connected, or the piping design of the pipeline
Now, the direction of the pipe force is perpendicular to the container’s centerline; the X-axis is defined as being perpendicular to the container’s centerline (pointing outward). The angle between the resultant force in the xyz directions and the X-axis is an obtuse angle. So, should the azimuth angle of the pipe force F be entered as an obtuse value, or should the magnitude of the pipe force F be entered as a negative value?
This post was last edited by wanlirn on 2021-8-23 at 15:34. You can choose any direction; just enter it for all the connection directions of this device. If there is only one connection, then no entry is necessary. Previously, we would combine all the centrifugal forces based on the azimuth angle and sum up the torque generated by all external forces, in addition to the pressure exerted by the foundation surface； Now the software does the calculation for you. .
This post was last edited by wanlirn on 2021-8-23 at 15:39. The direction is considered positive when it is downward; the direction is the angle with the X-axis, and 0 degrees can be chosen arbitrarily； But I’m used to following the nozzle orientation diagram, so it’s easier to verify later ；
1. When calculating the nozzle force on the cylinder of a calculation tower, should one use a force perpendicular to the container’s centerline? When calculating the nozzle force on the head of a calculation tower, should the force be chosen to be parallel to the container’s centerline? 2. If the X-axis is set perpendicular to the flange surface of the pipe, the Y-axis is parallel to the centerline of the container, and the resultant force in the xyz directions lies within the -x, y, z quadrants, then is the value of this resultant force negative? And what is the direction of the resultant force, in terms of the angle it forms with the X-axis?
1. Force on the nozzles of the tower’s cylinder – there are forces perpendicular to the container’s centerline, as well as forces parallel to it； The head is the same. 2. The X-axis is perpendicular to the flange sealing surface and is considered as the first force ； The Y/Z resultant force, parallel to the flange sealing surface, acts as the second force.