Calculation of heating time for heat transfer oil
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Given: A 120kw heating element is used to heat 1.6 m3 of heat transfer oil from 20°C to 180°C. Determine the heating time. Query data: The specific heat of oil is 0.5 kcal/kg, the density of oil is 0.85 g/cm3, and 1 kW equals 860 kcal. Calculation formula: KW = W × Δt × C / (860 × T), where W is the weight of the heat transfer oil, Δt is the temperature difference, and C is the specific heat. For 120KW, the calculation is 1.6*1000*0.85*（180-20）*0.5/（860*T); T = 1.05 hours = 63 minutes. May I ask whether this formula can be used for calculations without taking into account heat losses? If actual operating conditions are taken into account, how should it be calculated? 17 cities in Shandong Province [Let’s chat]
The above formula takes into account only the heating time under ideal conditions, without considering practical factors such as heat loss from the heat transfer oil and the heat transfer efficiency of the heating tubes. In actual operating conditions, it is also necessary to take into account factors such as the heat loss of the heat transfer oil during the heating process and the heat transfer efficiency of the heating tubes; these factors all affect the calculation of the heating time. Therefore, in practical applications, more accurate calculations are required, or the actual heating time must be determined through experiments. .
Is a specific heat of 0.5 kcal/kg for heat transfer oil correct? If I use a 150kw heating element under actual operating conditions, can it complete the heating process in 60 minutes?:)
Physical property parameters are definite and unique. In calculations, it is crucial to take heat loss into account. An increase of over 30 can be added based on the calculated heat load
The heating power of heat transfer oil can also be determined using this formula
In other words, considering actual operating conditions, does it take at least a 150 kW heating element to heat 1.6 m3 of heat transfer oil to 180°C in one hour?
Is it feasible to use a 150kw heating tube under actual operating conditions?
The heating and dehydration time of the heat transfer oil must be taken into account. The heating is too fast; there are too many accidents
The units must match; it should be 1 kw.h = 860 kcal. Therefore, there is no error in the calculation process – one only needs to take into account heat losses and thermal efficiency.