! Does the amount of evaporation remain the same when water boils under different pressure conditions?
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In the concentration vessel (evaporation tank + condenser), when water is boiled at different pressures – for example, at 0.02 MPa, 0.04 MPa, 0.06 MPa, 0.08 MPa, and 0.1 MPa (at atmospheric pressure) – will the amount of evaporation be the same, given that the degree of boiling is consistent (that is, the water boils and bubbles in the same way, with no difference in boiling intensity between the vessels)? Or is it that the lower the air pressure, the greater the amount of boiling and evaporation?
With the same amount of heat input, the higher the pressure, the greater the amount of evaporation
Once the temperature reaches the boiling point, the rate of water evaporation depends on the heat power supplied!
It depends on the initial condition; if the initial conditions are the same, low pressure results in greater evaporation
It depends on the amount of heat input; when the heat amount is the same, the evaporation rate is generally consistent. The value for low pressure should be slightly higher, as a lower pressure corresponds to a lower operating temperature, which results in a slightly higher heat utilization rate – an increase that is almost negligible
What do you mean by \"boiling in Chengdu\"? Literally speaking, the amount of evaporation is the same. Moreover, the evaporation rate isn’t determined by the type of vehicle; it’s determined by the amount of heat absorbed. The reason for choosing a certain system for use in mortgages is not that it saves heat, but rather because there is a large temperature difference between low-grade heat sources and high-grade heat sources.
Thank you all. Based on my actual experiments, when considering the level of condensate collected from the condenser per hour under different pressure conditions, the rate of evaporation is not linear. In other words, it’s not the case that evaporation is highest at normal pressure (with a boiling temperature of around 100 degrees) or lowest at the lowest pressure (with a boiling temperature of around 55 degrees); rather, the fastest evaporation rate occurs at pressures between 0.04 MPa and 0.05 MPa (with a boiling temperature of around 65 degrees). Since the process is carried out manually, and the degree of boiling is determined by individuals based on visual inspection of the container, there may be some variations. I am currently working on some projects related to energy conservation and reduction, which is why I have this question.
Water boils at different pressures, and the rate of evaporation varies when the same amount of heat is applied. Higher pressure results in a lower latent heat of vaporization.
After the temperature reaches the boiling point, pv=nrt, and the amount of water that evaporates depends on the heat supplied! Evaporation amount has nothing to do with pressure.
When the temperature reaches the boiling point, according to PV=nRT, the amount of water that evaporates depends on the heat energy supplied. It has nothing to do with pressure
I know that the rate of evaporation is proportional to the heat absorbed. So let me rephrase my question: if there is a numerical value indicating the degree of boiling, where 0 represents no boiling, 50 represents normal boiling, and 100 represents violent boiling, then at what pressure would the most heat be absorbed, assuming that the degree of boiling remains at 60 under different pressures?