Calculation of flue gas condensation water volume
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It is known that the volume of saturated wet flue gas after desulfurization is 191,914 Nm3/h, and the temperature of the flue gas drops from 56°C to 48°C. What is the amount of flue gas condensate formed?
By looking at the partial pressure of water vapor at those two temperatures and comparing it with the pressure of the mixture of water vapor and exhaust gases at that time, it is possible to calculate the proportion occupied by water vapor. The condensation volume can be calculated by using 191914 m3/h. This is just my personal opinion for reference only.
Tables showing temperature and saturated water content can be found online, allowing for direct calculation
Can it be simplified? Just use the initial heating change of the flue gas to calculate the amount of steam condensate: Cp * (56 – 48) * M = latent heat * m
https://wenku.baidu.com/view/f9895fadbdd126fff705cc1755270722192e59c4.html
Check what the saturated water content of the flue gas is at the two temperatures; subtracting one value from the other will give the result
This requires looking up tables in engineering thermodynamics.