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A tank is equipped with three level gauges, A, B, and C. The height of the tank is 2 meters, and the density of the medium inside it is 1.15. The levels of liquids in gauges A and B are at 60%. C is a double-flange differential pressure level gauge. The header shows that the liquid level is 58%, assuming the pressure is 12 KPA. How to set the liquid level of liquid C to 60%? What are the calculation steps? Silicone oil density: 0.9
Using Δp=ρgh, the calculated differential pressure range is 22.54 Kpa. If the current pressure is 12 Kpa and 58% is displayed, and without considering the issue of scale shift, the range is set at 0–22.54 Kpa. To achieve a reading of 60%, the calculations are as follows: 1. 22.54 (range) * 60% = 13.524 Kpa – this is the pressure required for a 60% display. 2. 12 (current pressure) – 13.524 (required pressure) = -1.524 Kpa; this indicates that the range needs to be adjusted downward by 1.524 Kpa, to the range of -1.524–21.016 Kpa.
Furthermore, there is a problem with your question itself: if the three level gauges use different measurement methods, it’s normal for discrepancies to occur (for example, with radar or ultrasonic level gauges). If the range of the double-flange transmitter is adjusted arbitrarily, it will also give inaccurate readings in other locations. 2. Are the measurement ranges of 2 or 3 gauges the same? If not, the measurements will also be inaccurate.
What I really want to say is that I would like to know the calculation process. Thank you