I have a question and I hope someone experienced can help answer it. I don’t understand the combustion method used in sulfur recovery – why can one-third of the hydrogen sulfide be completely burned? rather than all of the hydrogen sulfide undergoing incomplete combustion

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The direct current method, also known as the partial combustion method, is used when the acid gas concentration is greater than 50%. In this method, all of the acid gas enters the reaction furnace, and it is necessary to control the amount of air supplied precisely in order to ensure that all the hydrocarbons in the acid gas are completely burned. Only 1/3 of the H2S is oxidized according to the reaction H2S + 1/2O2 → S + H2O; the remaining 2/3 of the H2S then undergoes catalytic conversion together with the oxidized SO2, in an optimal ratio, in order to achieve a higher conversion rate. ) How is the amount of oxygen introduced during this process quantified? Is it calculated based on 1/3 of the H2S that participates in the reaction? If that’s the case, wouldn’t there be a lack of oxygen? No SO2 would be produced, and instead an incomplete combustion reaction would occur: H2S + 1/2 O2 → S + H2O, resulting in the formation of elemental sulfur. In that situation, it would be impossible to ensure the proper amount of SO2 for subsequent reactions, right?