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[Q&A Question 182] 2018.07.06

2018-07-06View Original

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【Q&A Question 182】July 06, 2018: It is known that a certain oxidation-state catalyst contains 12% (by mass) oxygen. A total of 50 tons of this catalyst are present in the reactor. During the presulfurization process, 0.8 tons of pure sulfur, which is used as the sulfurizing agent, is lost. What is the minimum amount of sulfurizing agent required to complete the presulfurization of all the catalyst? (Sulfur content in the vulcanizing agent: 60%) Solution: The amount of vulcanizing agent required = (50×0.12×32/16+0.8)÷0.6 = 21.3 tons. (Unless otherwise specified, all questions and answers are based on hydrogenation units.) ) Correct: 3 wealth, Incorrect: 1 wealth ; Mass posting of posts – rated based on the lowest score ; Replies that are unrelated to the answer are considered spam and will be deleted immediately. For management purposes, if you need to view content from a few days ago, please go to https://bbs.hcbbs.com/home.php?mod=space&uid=3862647&do=thread&view=me&from=space through the summary post below. The APP short-video skills competition has started! https://bbs.hcbbs.com/forum.php?mod=viewthread&tid=1951670
Reply #22018-07-06
Required sulfurization dose = (50×0.12×32/16+0.8)÷0.6 = 21.3 tons. The minimum sulfurization dose required for pre-sulfurizing the entire catalyst amount is 21.3 tons.
Reply #32018-07-06
Required sulfurization dose = (50×0.12×32/16+0.8)÷0.6 = 21.3 tons. The minimum sulfurization dose required for pre-sulfurizing the entire catalyst amount is 21.3 tons
Reply #42018-07-06
Answer: Solution: The required amount of sulfurization agent = (50×0.12×32/16+0.8)÷0.6 = 21.3 tons
Reply #52018-07-06
Sulfurization dose = (50×0.12×32/16+0.8)÷0.6 = 21.3 tons. The minimum sulfurization dose required for pre-sulfurizing the entire catalyst amount is 21.3 tons
Reply #62018-07-06
Required sulfurization dose = (50×0.12×32/16+0.8)÷0.6 = 21.3 tons. The minimum sulfurization dose required for pre-sulfurizing the entire catalyst amount is 21.3 tons.
Reply #72018-07-06
Required sulfurization dose = (50×0.12×32/16+0.8)÷0.6 = 21.3 tons. The minimum sulfurization dose required for pre-sulfurizing the entire catalyst amount is 21.3 tons

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