200 cable tray
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How many armored 10*1.5mm2 cables can fit in a 200 cable tray?
Is the tray 200*100, or some other model? The total area is simply the cross-sectional area of each tray multiplied by 80%.
For control cables: The width of the cable tray is b = S/h = S0/40%h (where S = S0/40%). Here, S0 = n1*S1 + n2*S2 + n3*S3 + ……, and n1, n2, n3… represent the number of cables of each type； S1, S2, S3... represent the cross-sectional areas of each cable (calculated based on the cable’s outer diameter) ； S----Cross-sectional area of the tray space h----Net height of the tray space
The \"Code for Design of Instrumentation Piping in Petrochemical Industries\" SH/T3019-2003 specifies that the filling rate for instrument cable trunking should be between 0.25 and 0.35
This post was last edited by backhamm1982 on 2015-6-10 10:52. What is the height of 200? Is it the main tray or a branch?
For armored cables, loads also need to be taken into consideration. Generally, with a spacing of 1.5 meters between supports, they can handle an average load of 3000 N/m; in simpler terms, for a cable tray that is 200 meters wide, the load per meter for nuclear power cables should be less than 200 kilograms. If the load does not exceed the limit, the volume occupied by the cable tray is generally no more than 85%; for the cables, it is sufficient to calculate based on a roughly square cross-section corresponding to their diameter.