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2015-08-13View Original

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This post was last edited by zhaoyuan214 on 2015-8-13 10:26. What is the equation for the autopolymerization of isobutylene to form diisobutylene? Isoprene has several different names – is (2,4,4-trimethyl-1-pentene) and (2,4,4-trimethyl-2-pentene) both correct? Which one is more? )? Is its heat release greater than that of the main reaction? I hope someone can help answer this question. Thank you all:hug:
Reply #22015-08-27
The amount isn’t very clear, but the heat release should be about twice that of the main reaction.
Reply #32015-08-28
Thank you. I checked in the book \"Engineering of C4 and C5 Olefins\" and found that the exothermicity of the main reaction is 36.52 kJ/mol, while the exothermicity of the auto-polymerization of isobutylene to form 2,4,4-trimethyl-1-pentene is 69.34 kJ/mol. I’m not sure whether these values for the product and the exothermicity are correct (I have seen different values for both). Can you confirm that the exothermicity of the side reactions involved in the auto-polymerization of isobutylene is definitely greater than that of the main reaction? And is this the only reaction product of isobutylene self-polymerization?

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