Why does the temperature drop in each reactor decrease sequentially during reorganization? What are the factors that affect the temperature drop in reactors?

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The temperature drop in the reforming reactor is caused by endothermic reaction processes. A typical endothermic reaction is the dehydrogenation of hexacyclic alkanes; this reaction has a large heat absorption value, proceeds easily, and occurs almost quantitatively. As a result, it takes place mainly in the first reactor, which is why the temperature drop is greatest in that reactor. In the subsequent second and third reactor stages, the cyclohexane dehydrogenation reactions decrease gradually. The reactions that occur thereafter are mainly those that are difficult to carry out and require higher temperatures, such as pentacyclic isomerization, alkane dehydrogenation cyclization, and hydrocracking. The reaction rates for these reactions, as well as the resulting temperature drops, are clearly lower than those in the cyclohexane dehydrogenation process. During the conversion process, many factors affect the heat effect, among which the main factors influencing the temperature drop of the reaction are: (1) the composition and activity of the catalyst; (2) the properties and composition of the feed oil; (3) the reaction pressure; (4) the hydrogen-to-oil ratio; (5) the space velocity; (6) the operating conditions; (7) the reaction temperature. So the question is: what causes the large temperature drops in the second and third reverse reaction sections of the four-reverse reforming reactor system?