How is the steam consumption of a double-effect concentrator calculated?
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How is the steam consumption of a double-effect concentrator calculated? Do any experts have any good experience formulas to share?
Isn’t this solved through material balance and energy balance?
It’s definitely not that simple; the steam generated is first evaporated, and the resulting primary steam is then used as a heating source for the second stage of concentration. This is very different from the calculations involved in single-stage concentrators! Although it’s always those same formulas!
Knowledge of chemical engineering principles is available in books!
In the principles of chemical engineering, calculations are only available for single-effect systems; there are no specific examples for double-effect systems! ! ! ! ! !
If you understand well, can you find specific calculation examples?
It’s meaningless to calculate this; in actual operation, for a single-effect system the ratio is roughly 1.2/1, while for a double-effect system, 0.55–0.6 tons of steam are required per ton of water evaporated. Due to heat losses and other factors, it’s not possible to calculate everything based on thermal balance
Calculated based on material and heat balance, there is no unified standard; it can be found in textbooks on chemical engineering principles.
It’s quite professional, haha – really good