How are the various stresses calculated by Caesar combined to form normalized stresses?
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The stresses calculated by Caesar2014 include: axial stress: 1222.07, bending stress: 4209, shear force: –488, circumferential stress: 2500, and maximum stress: 5517.93. How can these values be combined to obtain the standard stress of 4486? The above are the results of the initial stress calculations; the unit for stress is kPa, and the B31.3-2012 standard is being used Why is the value calculated using the stress formula specified in the standards 5517.93, while the standard stress value is 4486?
This post was last edited by wanliqingkong on 2016-2-26 at 10:29. The secondary stresses include: axial stress: 125.94, bending stress: 20772, shear force: 209, circumferential stress: 0; the maximum stress is 20902.24, and the value according to standards is 22325. How is 22325 obtained as the stress value per standards? The above are the results of the secondary stress calculations, with stress values expressed in kPa, using the B31.3-2012 standard Why is the value calculated using the secondary stress formula specified in the standards 20902.24, while the standard stress value is 22325? To verify the results from version 2014, I ran case178 using version 5.0, adding f/a to the strerss configuration. The result for the primary stress was the same as that obtained in version 2014, and the secondary stress values also matched those from version 2014. The only difference was that the normative secondary stress calculated by version 5.0 was 20902, which coincided with the maximum stress value in both version 2014 and version 5.0. Why did such a result occur?
I’ve encountered this problem too. Could the original poster explain it?
Could the original poster specify which standard and which formula to use? Some domestic standards differ from 31.1 and 31.3