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It is known that the volume of semi-water gas is 100,000 m3, with a hydrogen content of 45%, a pressure of 1.9 MPa, and a temperature of 35°C. The steam temperature in the gas generator is 200°C and the pressure is 26 KPa. How can the amount of steam required for the gas generator be calculated? Here are my own calculations: The hydrogen content in semi-water gas is 45,000 m3. At 1.9 MPa/35°C, the density of hydrogen is 1.4787 kg/m3. The mass of hydrogen is therefore 1.4787 * 45,000 = 66,541.5 kg. The molar mass of hydrogen is 66,541,500 / 2 = 33,270,750 moles. Since 1 mole of water vapor produces 1 mole of hydrogen, the amount of water vapor required is 33,270,750 * 18 = 59,887,3500 grams, which is approximately 600 tons. Why is the calculated amount of steam so large? I feel like there’s definitely something wrong; I just don’t know what it is. I hope the experts here can help me figure it out
What kind of vaporizer is being used? Why is the gas pressure so high? That’s why your steam pressure is so low.
Pressure has a significant impact on the calculation results. The steam is not 100% decomposed; what does not react turns into wastewater. You missed one piece
1.9 MPa is the pressure after three stages of compression by the compressor; the inlet pressure for the first stage is 30 KPa
I know that pressure has a significant impact. According to the law of conservation of mass, I calculated the actual amount of water vapor involved in the reaction in the gas generator by using the molar mass of three molecules of H2. Based on my calculations, the actual amount of water vapor used in the reaction is 600 tons; plus the amount that remains unreacted and ends up as wastewater, the total amount is even higher. There must be some mistake in my calculations
Can the original poster be 100% sure that 100,000 represents the actual volume rather than the standard volume? ? The output is supposed to be nearly 600 tons of amino alcohol/h? ? ?
The poster’s 100,000 volume unit must be cubic meters
10,000 is the volume at standard conditions; the density should be 0.089 kg at standard conditions/
100,000 represents the volume at standard conditions; the density should be calculated based on 0.089 kg/m3 for hydrogen under standard conditions, rather than using the density of 1.4787 kg/m3 for hydrogen at 1.9 MPa/35°C. Thank you for the reminder
100,000 represents the volume at standard conditions; the density should be calculated based on 0.089 kg/m3 for hydrogen under standard conditions, rather than using the density of 1.4787 kg/m3 for hydrogen at 1.9 MPa/35°C. Thank you for the reminder