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【Daily Question】Chemical Engineering Principles 358: Industrial Water Pumps (April 11)

2016-04-11View Original

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The Chemical Engineering Theory section is launching the \"One Question per Day\" campaign starting today, aimed at helping everyone reinforce their basic knowledge in chemical engineering. Subsequent series will include those on \"Principles of Chemical Engineering,\" \"Mass Transfer and Separation,\" \"Thermodynamics in Chemical Engineering,\" and \"Chemical Process Engineering.\" We hope you will give it your active support! Wishing you a happy Christmas! Answers to the questions in the \"One Question per Day\" campaign can be viewed directly by replying to the post, and the thread will be closed after 1 day ! To encourage continued participation from everyone this year! You get 3 wealth points for participating, and an additional 4 wealth points for answering correctly~~~ Short answer question: What are the power and flow rate of industrial water pump motors? 190 KW, 790 T/H
Reply #22016-04-11
The power and flow rate of industrial water pump motors are determined based on industrial requirements.
Reply #32016-04-11
Is this question ambiguous?
Reply #42016-04-11
190 KW, 790 T/H
Reply #52016-04-11
Power is 190 KW and flow rate is 790 T/H
Reply #62016-04-11
This question cannot be answered; the flow rate depends on production requirements, while the power level depends on both the flow rate and the head
Reply #72016-04-11
The power of the water pump, W, is given by the formula W = λ * (q * h * 10^10) / (3600 * η), where W is the power in kW, q is the flow rate of the water pump in m3/h, h is the head of the water pump in meters, and λ is the safety factor for the water pump; generally, λ takes values between 1.2 and 1.25; η is the efficiency of the water pump, with η ranging from 0.7 to 0.85.
Reply #82016-04-11
It depends on the specific situation! The rated power, rated flow rate, and rated motor power can be found on the nameplate!
Reply #92016-04-11
Q=UICOS∮*1000/3.6H
Reply #102016-04-11
190 KW, 790 T/H

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