Resistance and power
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How to determine resistance diameter and power
For the same material, the larger the diameter, the lower the resistance. You can take a look at the heating wire of an electric furnace: the thicker it is, the lower the resistance and the greater the power.
R=ρL/S (where ρ is the density of the material, L is the length, and S is the cross-sectional area); S=π(D/2)2, and W=U2/R. Using these formulas, we can derive that the power W=U2πD2/4ρL. Therefore, the larger D is, the greater W becomes