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The motor drives the chain to rotate; its speed is 1400 rpm with a frequency of 50 Hz. The reduction gear has a speed ratio of 26.93, and the frequency of the inverter varies within 70 Hz. So how do we calculate the speed of the chain? Is the maximum speed of the chain 1400/26.93, or 1400*70/26.93? If the frequency of the inverter is represented by A, how is the chain speed calculated? S=1400/26.93*A/50? Seeking advice.
The speed of the motor is proportional to its frequency; that is, the motor speed R = 1400 * (70/50), and the chain speed = R/26.93
Is that so? If the frequency of my inverter can be increased further, will the speed keep rising? Does it depend on the rated frequency?
It will definitely increase. What you need to worry about is whether your motor can handle it, not whether the speed will increase or not
Theoretically speaking, does the inverter provide a constant power output when its frequency exceeds 50HZ? Is the relationship between speed and frequency still linear, given by n=60f/p at this point? Another question: isn’t the maximum speed of the chain R/26.93, but can it reach R/26.93*A/50? (A is the frequency of the inverter, which can be varied)
Are there any other experts who would like to share their opinions: handshake
The frequency indicated by this inverter should be 70%; the actual frequency should be 50 Hz, and 70% of that gives an actual frequency of 35 Hz
The actual speed of the motor, n1, is equal to 1400*70/50; the motor’s maximum speed and slip rate also come into play here, but they can be ignored; The rotational speed n2 of the reducer’s output shaft is equal to n1/26.93; this is also the rotational speed of the sprocket ; The angular velocity of the chain can be calculated from the rotational speed of the sprocket, while the linear velocity of the chain can be determined using the radius of the sprocket ;
If that’s the case, the speed difference will be quite large.