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When calculating the pump head, it is necessary to account for the pipeline resistance of the reducer, and HG20570 provides two formulas for this purpose. It’s quite troublesome. The chief engineer said that one could refer to page 54 of the \"Chemical Process Design Manual (5th Edition), Volume 2,\" but what is given there is the local resistance coefficient K. Equivalent length is used elsewhere in the table. He gave a watch. The origin isn’t mentioned. Some of the specifications were missing, so I handled it by using the insertion method. I just don’t know what the accuracy of this watch is. Due to space constraints, this is just the tip of the iceberg; it’s meant to serve as a starting point for further discussion.
This post was last edited by fmch6605 on 2024-8-23 15:05. What does it mean, based on the small tube end or based on the large tube end? I don’t understand. Could you explain it using the data in the table? For example: Taking 40*20 for the large tube end as a reference, what do increasing by 16.46 and decreasing by 7.32 mean respectively? Can you illustrate it with a diagram? Thank you
Taking the outlet of a DN20 pump as an example. Pump outlet 20, equipped with 40*20 reducers, connected to a DN40 main pipe thereafter. The entire pipe section is calculated as DN40. This is a case of amplification. There is a reduced-diameter section of 40*2 later on, connecting to DN 20 thereafter; it represents a condition of reduction in diameter. The diameter before the reducer is also calculated as DN40.