Thread Content
This post was last edited by kareale88 on 2018-9-25 at 11:44. I hope everyone will participate actively; I’ll compile the answers later. Thank you! @
Pressure = density * 9.81 * height. Just calculate it
1. There is a question in your query: whether it refers to the pressure used for hydrotesting or the static pressure under operating conditions. If it’s a hydrostatic test, do you carry it out with your equipment standing? 2. According to your diagram, 10.33 meters equals 0.1 MPa; the static pressure on the lower head is 0.0354 MPa, on the lower cylinder it is 0.03272 MPa, and on the upper cylinder it is 0.01336 MPa. Static pressure on the upper head: 0.00368 MPa
1、(3760-(380-275))/10.33 2、3380/10.33 3、1380/10.33 4、380/10.33 :)
1. (3760 – (380 – 275)) / 10.33 2. 3380 / 10.33 3. 1380 / 10.33 4. 380 / 10.33 What are 1, 2, 3, and 4? Which height should be used?
1. Static pressure on the lower head: 0.0354 MPa, 2. Lower cylinder: 0.03272 MPa, 3. Upper cylinder: 0.01336 MPa. 4. Static pressure on the upper head: 0.00368 MPa
1. Static pressure on the lower head: 0.0354 MPa, 2. Lower cylinder: 0.03272 MPa, 3. Upper cylinder: 0.01336 MPa. 4. The static pressure on the upper head is 0.00368 MPa, in this order.
If the hydrostatic test is conducted horizontally, how is it calculated? Thank you
This post was last edited by zjq1962 on 2019-7-25 at 16:25. The formula for calculating the hydrostatic pressure of a liquid column (for water) is =1000*H*9.81*10-9. In the formula, H is in mm, and the calculation result is in MPa; based on this, the value provided by the original poster seems to be incorrect as well. In order: 0.0358 ; 0.03316 ; 0.0135 ; 0.00373