SW6 V5.0 pressure-area method welding joint coefficient
Thread Content
The welding joint coefficient for the pressure-area method in SW6 V5.0, according to the latest version of this software, requires a welding joint coefficient of 1 for both the shell and the nozzles. This results in relatively high costs
After reviewing the standard requirements, it only stipulates that welding should not be carried out on welds; SW6 increases the difficulty of use
100% RT Class II qualified!
Everything is done according to standards these days; the calculation software simply reminds you of the requirements set by those standards. As for how to implement them, that depends on the design and manufacturing processes
Personal opinion: Try to avoid having welds within the area intended for reinforcement through drilling; if welds cannot be avoided, then all welds on the pipe connections as well as those within the reinforcement area should undergo 100% non-destructive testing. It is not necessary to conduct 100% non-destructive testing on the entire equipment
How much will this increase the cost? It’s not that the entire design is 100% perfect; it’s just said that the openings should not be located on the welds of the casing. For a 630*8 seamless tube, only a short section is required, and it costs a little more. In that case, sheet metal is used, and that constitutes 100% perfection. As for the length of the connecting pipe, it simply depends on the size of the sheet metal used
The pressure area method is not included in the calculation methods for opening reinforcement specified in GB/T150; moreover, the bending stress at the edges of large openings often plays a more significant role. Therefore, it is necessary to increase the welding joint factor of the cylinder surrounding the opening.
Welds within a range of 2 times the opening diameter require RT-100%, while those outside this range are to be treated according to the cylinder standards.
It means that the welding joint coefficient within the reinforcement area is 1, which is similar to what the analytical method requires; the cost should not be much higher either
In SW6, the input joint coefficient is the \"longitudinal weld joint coefficient\". Guess whether circumferential joints are also checked in the calculations? If performing verification, how should the coefficient be chosen? If no verification is carried out, does that mean that if the longitudinal verification meets the requirements, then the circumferential verification must also meet the requirements?