Help: How to determine the moisture content (specific humidity) of flue gas! Urgent!
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Given a flue gas temperature of 150°C and a relative humidity of 10%, determine the water content in the flue gas (g/kg)!
First, consider the saturated vapor pressure of water at 150 degrees: 475.72 kPa. The partial pressure of water is equal to 10*475.72/100 = 47.572 kPa. Then, using the equation pv=nRT, the number of moles of water vapor in 1 m3 can be calculated； n=13.5273 mol, and the mass of water corresponding to this is m=13.5273*18=243.4 g; finally, you need to know the density of the smoke gases ； You need to calculate the density of the smoke based on the actual conditions ；
Hello, the molar amount of moisture in the flue gas is calculated as 47572*1=n*（273+150）*8.314. Is this calculation correct? Can volume and pressure be entered in this way?
Heat exchanger master calculation result: 338g/kg