Regarding the issue of the double-flange range
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For the new enamel-lined reactor used in the workshop, since there is no extra space at the bottom of the reactor, the high-pressure side with double flanges is installed on the pipeline at the discharge port at the bottom of the reactor; interfaces are provided on this pipeline, while the low-pressure side is installed at the top of the reactor. During normal production, the discharge pipeline, from the bottom of the tank to the flange on the high-pressure side, is properly filled with fluid, and the transmitter measures the liquid level inside the tank. I just want to ask how to set the range of the transmitter
Are you an instrumentation technician or a process engineer?
The range is the distance between the two flanges, which is h; the calculation formula is density × gravitational acceleration × h. However, this method for determining the liquid level is inaccurate, as the pressure on the high-pressure side certainly changes during discharge, so the liquid level will fluctuate.
Then you can see the answer on the 3rd floor**
But a pipeline pressure of about one meter at the bottom of the tank isn’t necessary; what’s needed is to eliminate this pressure level. The key issue is how to calculate the pressure on the high-pressure side
There is no need to calculate the pipeline pressure; you just need to measure the distance between the two flanges, use a formula to determine the range, and then proceed with the migration. But this liquid level is definitely inaccurate!
That’s more or less it; how to set the upper and lower limits for the transmitter
This post was last edited by zxg.wylton on 2017-4-14 at 15:29. I really don’t want it to be complicated; set it to L5.6kPa and U18kPa for now. Alternatively, when the liquid level just reaches the discharge pipe, set U to 18 kPa; then set L so that 4 milliamps are output. When the liquid level is full, change the value of U to 20 milliamps of output ； Or set it according to the transmitter manufacturer’s instructions. It’ll have to do; it’s impossible to get an accurate measurement of the liquid level.
How can the L value be +5.6 Kpa?