Conversion between outlet pressure and head of centrifugal pumps
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Assuming there is no height difference between the pump’s inlet and outlet, is the pump’s head then equal to the static pressure energy at the outlet? Is it H=△P/ρg? Well, there’s also kinetic energy. The data sheet for pumps usually only lists the inlet and outlet pressures, not the outlet velocity; does that mean it’s impossible to calculate the head?
It’s not that there isn’t any, but it’s very small and can be ignored. There are pump inlet and outlet diameters, as well as the pump flow rate; with these values, it’s possible to calculate the flow velocities at the pump’s inlet and outlet. However, the difference resulting from these calculations is quite small, so it can be ignored
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This post was last edited by Little Chemical Engineer on 2018-11-7 at 08:21. What nonsense are you rambling on about? Simply put, the head of a pump is calculated as the outlet pressure minus the inlet pressure, divided by ρg.
Your answer was spot-on; I admire it!
Someone asked whether it is related to changes in kinetic energy; please take a close look
Please take a good look before saying yes, okay? Do you understand what inlet pressure and outlet pressure of a pump are? If the pump inlet is a device (or a tank) to which the inlet pipe is connected, what is the pump’s inlet pressure? What can you detect? All you can know is the pressure in the tank; the pressure loss in the inlet pipe needs to be calculated, based on the flow rate. The inlet pressure is calculated using these two parts. The same goes for the outlet pressure! You ask, is it related to changes in kinetic energy when calculating pipe losses? !
Typically, the head of a water pump is determined by the sum of the height difference between the pump outlet and the delivery location, as well as the pipe losses along the route. Although there is no height difference, as long as a pump is used to transport a medium, there will be pipeline losses.
I’m here, not to be questioned; please stop using so many rhetorical questions. Just answer the questions one by one properly. Make sure the person asking the question understands what you are saying.
I told them, why are you getting so upset for no reason?