Daily Question June 30, 2015 (EIA Discussion): 3 Wealth points as a reward for replying, plus 5 Wealth points for a correct answer
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This post was last edited by Zhang Xiaopeng on 2015-6-30 at 18:31. The wastewater inflow to the wastewater treatment plant for a certain chemical industry project is 10,000 m3/day, with a COD concentration of 1,500 mg/L. The total COD removal rate is 90%, and the wastewater reuse rate is 50%. What is the amount of COD discharged from this wastewater treatment plant? A. 0.75 t/day B. 1.5 t/day C. 7.5 t/day D. 15 t/day 【Answer】A. Explanation: 10,000 m3/day * 1,500 mg/L * 1,000 * (1–90%) * (1–50%) = 0.75 t/day
A. 0.75t/d
The inflow volume to the wastewater treatment plant for a certain chemical project is 10,000 m3/day, with a COD concentration in the influent water of 1,500 mg/L. The total COD removal rate is 90%, and the wastewater reuse rate is 50%. The amount of COD discharged from this wastewater treatment plant is (A).
A. 0.75t/d
Answer: A. 0.75t/d
A. 0.75t/dA. 0.75t/dA. 0.75t/dA. 0.75t/d
The inflow volume to the wastewater treatment plant for a certain chemical manufacturing project is 10,000 m3/day, with a COD concentration in the inlet water of 1,500 mg/L. The total COD removal rate is 90%, and the wastewater reuse rate is 50%. What is the amount of COD discharged from this wastewater treatment plant? A. 0.75 tons/day
The inflow volume to the wastewater treatment plant for a certain chemical project is 10,000 m3/day, with a COD concentration in the inlet water of 1,500 mg/L. The total COD removal rate is 90%, and the wastewater reuse rate is 50%. What is the amount of COD discharged from this wastewater treatment plant per day? D. 15 tons/day