Given the components of a gaseous fuel, how can its calorific value be calculated?
Thread Content
As the title indicates, it is known that the components of this gas are 79.4% methane, 2.68% ethane, 2.3% isobutane, 3.01% n-butane, 0.92% isopentane, 0.58% n-pentane, and 0.46% n-hexane; there are also other substances present, but their volume percentage is so small that they can be ignored. How to calculate the calorific value and methane value of this gaseous fuel?
The calorific value is approximately 4.879e4 KJ/KG. (The calculated value of the composition normalized according to the above percentage levels) Methane value: It’s not clear how to calculate it.
Thank you for your reply! The volume numbers of the various components in the question are the molar volumes
Methane value: 66.7 Heat value: 1003.7 BTU/FT^3
Physical chemistry has this calculation...
Use process simulation software directly – it can be calculated in just a few minutes
That’s not fair of you; others have spent ages calculating the values, and then you show up with a mol%
Thank you! Could you explain your calculation process? Also, the project has now seen additional requirements: light hydrocarbons need to be recovered and water needs to be removed. What are the methane value and calorific value of the recovered light hydrocarbons and the dehydrated methane, respectively? The dew point after dehydration is -55 degrees.