Question 3 in the morning of 2014
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The initial temperature for a certain chemical reaction is 25°C. When the temperature increases by 12°C, the reaction rate doubles. What is the activation energy of this reaction in J/mol? Is it calculated using the formula k=k0exp(-E/RT)? It seems like I’ve tried calculating it several times, but I can’t figure it out. This afternoon there was another similar problem, and I couldn’t work out the answer. So I’d better consult an expert right away to avoid encountering such case questions tomorrow
I just calmed down and did it again, and then the calculation was completed. Be sure to note that the unit of activation energy E is J/mol
Yes, I remembered it at the last minute as well